Show that ∫01 dx/√(-logx) =√π
Answers
Answered by
1
Answer:
∫
x
logxdx
=logx∫
x
dx−∫
x
1
⋅
3
2
x
3/2
dx, Use by parts
=
3
2
x
x
logx−
3
2
∫
x
dx
=
3
2
x
x
logx−
3
2
⋅
3
2
x
x
+C
=
3
2
x
x
logx−
9
4
x
x
+C
Explanation:
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