Question

Show that (1)+(1+1)+(1+1+1)+...+(1+1+1+ ... +n times) =n (n+1)/2​

Answer 1

Answer: N

Step-by-step explanation:

1 is logical and second one is with sum of AP series

1+1+1+1+1+1+….n time

see here you can se 1+1=2 (first two numbers)

2+1=3 (sum of first two numbers +third number)

so by going this way the last two terms will be

(n-1)+1=n

second way to do so,

sum of AP= n/2{a+l}……(n is number of terms, a is first number and l is last number)

so in the given equation (1+1+1+1…n terms)

sum,

=n/2{1+1}

=n/2{2}

=n

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