Show that 1,1/2,and-2 are the zeroes of the polynomial 2xcube+xsquare-5x+2
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Hey here is ur answer
p(x) = 2x^3+x^2-5x+2
p(1)=2×1^3+1^2-5×1+2
=2+1-5+2
=5-5
=0
p(1/2)=2×(1;2)^3+1(1/2)^2-5×1/2+2
= 2×1/8+1/4-5/2+2
=1/4+1/4-5/2+2
=1+1-10+8/4
=10-10/2
=0/2
=0
p(-2) = 2×(-2)^3+(-2)^2+-5×-2+2
=2×-8+4+10+2
= -16+16
=0
Hone p(x) = 0 all the time
So 1, 1/2 and -2 are the zeroes of the polynomial
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