Question

Show that 1, -1 and 3 are the zeroes of the polynomial x^3 - 3x^2 - x + 3
(2 Marks)

Answer 1

Answer:

the question is wrong boy .

Answer 2

1, -1, and 3 are the zeroes of the polynomial

Step-by-step explanation:

Given: $x^3 - 3x^2 - x + 3$

Using hit and trial error method,

For x=1,

$(1)^3 - 3(1)^2- 1 +3$

1-3-1+3=0

If the polynomial value is zero. It means x=1 is zero of the polynomial.

For x= -1

$(-1)^3-3(-1)^2-(-1)+3$

-1-3+1+3 =0

For x=3

$(3)^3-3(3)^2-3+3$

27-27-3+3 =0