Question

Show that (1, 1) as well as (4, 13) are the
solutions of the equation 4x-y-3=0.​

Answer 1

put x=1,y=1 in 4x-y-3=0.

4*1-1-3=3-3=0

put x=4, y=13 in 4x-y-3=0.

4*4-13-3=0

thus, proved

Answer 2

Answer:

Step-by-step explanation:

[1,1]

here , 1 = x and 1 = y { part 1 }

4x-y-3=0.

[4 x 1] - 1 - 3 = 0

4 - 4 = 0

0 = 0

Lhs = Rhs

hence,prooved

[ part 2 ]

[4,13]

here 4 = x and 13 = y

4x-y-3 = 0

[4 x 4] - 13 - 3 = 0

16 - 16 = 0

0 = 0

hence , prooved