Math, asked by duttapalkpa9255, 9 months ago

Show that 1/2 ,-3/2 are the zeros of the polynomial 4x^2 +3x+2 and coefficients of polynomial.

Answers

Answered by akshingarg5
1

Answer:

Step-by-step explanation:

Hii friend,

P(X) = 4X²+4X-3

=> 4X²+6X-2X-3

=> 2X(2X+3) -1(2X+3)

=> (2X+3)(2X-1)

=> (2X+3) = 0 OR (2X-1) = 0

=> X = -3/2 OR X = 1/2

Hence,

1/2 and -3/2 are the zero of the polynomial 4X²+4X-3

Let Alpha = 1/2 and Beta = -3/2

Relationship between the zeros and Coefficient.

Sum of zeros = (Alpha +Beta) = {1/2+(-3/2)} = 1/2 - 3/2 = 1-3/2 = -2/2 = -1 = Coefficient of X/Coefficient of X²

Product of zeros = (Alpha × Beta) = (1/2 × -3/2) = -3/4= Constant term/Coefficient of X².

HOPE IT WILL HELP YOU..... :-)

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