show that (1,2) (3,4) (5,6) are collinear
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Step-by-step explanation:
when the points are said to collinear their slope must be equal
Let A(1,2) B(3,4) C(5,6)
Slope = m = (y2-y1)/(x2-x1)
mAB = (4-2)/(3-1) => 2/2 => 1
mBC = (6-4)/(5-3) => 2/2 => 1
mAC = (6-2)/(5-1) => 4/4 => 1
Slopes are equal
Therefore they are collinear
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