Question

Show that 1,2,3 are the zeroes of p(x)= (x-1) (x-2) (x-3). Please help me.​

Answer 1

I hope it will help you

Answer 2

p(1)=1-1*1-2*1-3

0*-1*-2

p(1)=0

so,

p(2)=2-1*2-2*2-3

p(2)=1*0*-1

p(2)=0

also,p(3)=3-1*3-2*3-3

p(3)=2*1*0

p(3)=0

we just need to substitute 1,2,3 in x place