Question

show that 1,2,3 are the zeros of p(x) equal (x-1) (x-2) (x-3).

Answer 1

X=1
X-1=0

X=2
X-2=0

X=3
X-3=0

Answer 2

$Hey\:There$‼

Given, p(x) = (x – 1) (x – 2) (x – 3)

p(1) = ( 1 – 1 ) ( 1 – 2 ) ( 1 – 3 )
=> ( 0 ) ( – 1 ) ( – 2 )
=> 0 × 2
=> 0
Thus, 1 is a zero of given p(x).

p(2) = ( 2 – 1 ) ( 2 – 2 ) ( 2 – 3 )
=> ( 1 ) ( 0 ) ( – 1 )
=> 0 × (–1)
=> 0
Thus, 2 is a zero of given p(x).

p(3) = ( 3 – 1 ) ( 3 – 2 ) ( 3 – 3 )
=> ( 2 ) ( 1 ) ( 0 )
=> 2 × 0
=> 0
Thus, 3 is a zero of given p(x).