Show that 1/2 and -3/2 are the zeros of the equation 4x^2+4x-3
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Answer:
alpha+bita=-b/a
1/2+-3/2=-4/3
-4/2=-4/2
LHS=RHS
alpha*bita=c/a
1/2*-3/2=c/a
-3/4=-3/4
LHS=RHS
I HOPE IT WILL HELP YOU
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