Question

Show that 1,2 and 3 are the factors of the polynomial y³– 6y² + 11y – 6 step by step explanation for class 9

Answer 1

Answer:

Show that 1,2 and 3 are the factors of the polynomial y³– 6y² + 11y – 6

Step-by-step explanation:

Hello!

Given that,

If y=1

then,

= 1cube -6*1square+11 *1-6

= 1-6+11-6

= 0

Hence, 1 is factor of y³– 6y² + 11y – 6.

If y=2 then,

= 2cube-6*2 square+11*2 -6

= 8-6*4+22-6

=8-24+22-6

=0

Hence ,2 is factor of y³– 6y² + 11y – 6.

If y=3 then,

=3 cube-6*3 square +11*3-6

= 27- 6*9 +33-6

= 27-54 +33-6

=0

Hence, 3 is factor of y³– 6y² + 11y – 6.

I hope you are understand the problem