Show that 1, 2, and 3 are the zeros of f(x) = x3-6x2+11x -6 .
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f(x) = x^3-6x^2+11x-6
Substituting 1,2,3 in x
f(1)= 1-6+11-6
= -11+11=0. Verified.
f(2)= 8-24+22-6
=8-8 = 0. Verified.
f(3) = 27-54+33-6
= 0
Verified.
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