Question

Show that

1) 2(cos^2 45 + tan^2 60) - 6(sin^2 45 - tan ^2 30)=6

2) 2(cos^4 60 + sin^4 30) - (tan^2 60 + cot^2 45) + 3 sec^2 30= 1/4​

Answer 1

Answer:

given :

= 2{(1/√2) ²+(√3) ²} -6{(1/√2) ²-(1/√3) ²}

= 2(1/2+3) -6(1/2-1/3)

= 2(1+6/2) -6(3-2/6) (taking LCM)

= 2(7/2) -6(1/6)

= 7-1

= 6

hence 1 is found