Show that 1/2 gt² has the same dimensions of distance
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As distance has dimensions, [L]
If we look at 1/2 gt square
Here g is acceleration due to the gravity
T is time
As a has dimensions [LT-2]
And time has dimensions [T-2]
Using above we get that
[L] = [LT-2] /[T-2] which is equal to L.
Hope you get your answer.
If we look at 1/2 gt square
Here g is acceleration due to the gravity
T is time
As a has dimensions [LT-2]
And time has dimensions [T-2]
Using above we get that
[L] = [LT-2] /[T-2] which is equal to L.
Hope you get your answer.
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