Question

Show that 1/2 is a zero of р(х)=2x²+7x-4 ​

Answer 1

Put x = 1/2 in the equation

p(x) = 2x²+7x-4

p(x) = 2(1/2)²+7(1/2)-4

p(x) = 1/2 +7/2 -4

p(x) = (1+7-8)/2

p(x) = 0/2

p(x) = 0

Hence proved that 1/2 is a root of р(х)=2x²+7x-4 .

Kindly follow me and thank my answers, mark brainliest. ❤

Answer 2

Step-by-step explanation:

p(x)=2x2+7x-4

p(1/2)=2.(1/2)2+7.1/2-4

=2.1/4+7.1/2-4

=2/4+7/2-4

=(2-14-16)/4

=(16-16)/4

=0/4

=0

clear the meaning of point is multiplication.

thank u

stay safe and stay healthy