show that 1/2+root 3 is irrational
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Hello buddy..
We can rationalize the denominator of the above expression, & then we can proceed with our proof…
After rationalization
1 / (2+√3) * (2-√3) / (2-√3)
= (2-√3) / (4–3)
= 2-√3
Now, we can prove that 2-√3 is an irrational..
We assume 2-√3 is a rational ……(1)
=> 2-√3 = p/q ( where, p, q belong to the set of integers, q is not equal to 0)
=> 2- p/q = √3
Here, LHS is a rational number, as we know that the difference of 2 rationals is always a rational.
But √3 is an irrational ( It's a theorem)
=> in the above LHS should not be equal to RHS..
This contradiction arises because of our wrong assumption.
So, 2-√3 should be an irrational number…. (corrected our assumption (1) )
=> 1/(2+√3) is an irrational number
[ Hence Proved]
Hope it helps you buddy...
We can rationalize the denominator of the above expression, & then we can proceed with our proof…
After rationalization
1 / (2+√3) * (2-√3) / (2-√3)
= (2-√3) / (4–3)
= 2-√3
Now, we can prove that 2-√3 is an irrational..
We assume 2-√3 is a rational ……(1)
=> 2-√3 = p/q ( where, p, q belong to the set of integers, q is not equal to 0)
=> 2- p/q = √3
Here, LHS is a rational number, as we know that the difference of 2 rationals is always a rational.
But √3 is an irrational ( It's a theorem)
=> in the above LHS should not be equal to RHS..
This contradiction arises because of our wrong assumption.
So, 2-√3 should be an irrational number…. (corrected our assumption (1) )
=> 1/(2+√3) is an irrational number
[ Hence Proved]
Hope it helps you buddy...
RehanAhmadXLX:
Nice
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