Question

show that (-1+3^1÷2i)^3 is a real number​

Answer 1

Answer:

it's not a real no.

Step-by-step explanation:

(-1+3^1÷2i)^3 we know that i²=-1

=((3/2i)-1)³=((3-2i)/2i)³ after lcm

open cube

{27-8i³-18i(3-2i)}/8i³

={27+8i-54i+36i²}/-8i

={27+8i-54i-36}/-8i

=-9-62i/-8i

so it's not a real no.