Question

Show that:
1/(3-√8) + 1/(√7-√6) +1/(√5-2) - 1/√8-√7 -1/(√6-√5) =5

Answer 1

Answer:

there is no answer . only proving Question

Step-by-step explanation:

first of all rationalise the L.H.S side . we get

=> 1/3-√8 × 3+√8/3+√8

=> 3+√8/9-8

=> 3+√8

similarly rationalise all the terms . we get

√7+√6 , √5+2 , √8+√7 and √6+√5.

now putting these values in the L.H.S side

=>(3+√8)+(√7+√6)+(√5+2)-(√8+√7)-(√6+√5)

=> 3+√8+√7+√6+√5+2-√8-√7-√6-√5

by canceling the numbers

we get

=>3+2

=>5

L.H.S=R.H.S

Hence proved

Answer 2

Step-by-step explanation:

at the beginning of this question we have to know the root values

√8=2.828

√6=2.449

√5=2.236

√7=2.645

let us enter into the question

1/(3-√8)=1/(3-2.28)=1/(0.72)=1.389

1/(√7-√6)=1/(2.645-2.449)=1/(0.196)=5.102

1/(√5-2)=1/(2.236-2)=1/(0.236)=4.237

1/(√8-√7)=1/(2.828-2.645)=1/(0.183)=5.464

1/(√6-√5) =1/(2.449-2.236)=1/(0.213)=4.694

there fore the final answer =1.389 + 5.102 + 4.237 - 5.464 - 4.694 = 5.2 =5(approx)