Question

Show that 1/(3-√8) - 1/(√8-√7) + 1/(√7-√6)- 1/(√6-√5) + 1/(√7-6) =5

Answer 1

Answer:#MarkAsBrainliest

#MarkAsBrainliest

Step-by-step explanation:

1(/3-√8)*(3+√8)/(3+√8)-1/(√8-√7)*(√8+√7)/(√8+√7)+1/(√7-√6)*(√7+√6)/(√7+√6)-1/(√6-√5)*(√6+√5)/(√6+√5)+1/(√5-2)*(√5+2)/(√5+2)

=(3+√8)/(3)²-(√8)²-(√8+√7)/(√8)²-(√7)²+(√7+√6)/(√7)²-(√6)²-(√6+√5)/(√6)²-(√5)²+(√5+2)/(√5)²-(2)²

=(3+√8)/1-(√8+√7)/1+(√7+√6)/1-(√6+√5)/1+(√5+2)/1

=3+√8-√8-√7+√7+√6-√6-√5+√5+2

=3+2

=5

hence proved

I hope this answer helps you

plz #MarkAsBrainliest