Math, asked by hitakshimahajan2820, 2 months ago

show that 1/3 and 4/3 are zeroes of polynomial 9x^3-6x^2-11x+4 find third 0 of polynomial

Answers

Answered by barani7953
1

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Answered by aadesahaja06
1

Step-by-step explanation:

p(1/3)=9(1/3)³-6(1/3)²-11(1/3)+4

=9(1³/3³)-6(1²/3²)-11(1/3)+4

=9(1/27)-6(1/9)-11(1/3)+4

=(1/3)-2(1/3)-11(1/3)+4

=(1/3)-(7/3)-(34/3)+4

=[(1-7-34)/3]+4

=(-40/3)+4

=[(-40+4)/4

=36/4

=9

Sorry I can't show that 1/3 is zeroes of the polynomial

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