Question

Show that 1/3 and 4/3 are zeroes of the polynomial 9

3 − 6

2 − 11 + 4. Also

find the third zero of the polynomial.​

Answer 1

Answer:

-3

Step-by-step explanation:

Let f(x)=2x4+9x3+11x2+4x−6.

f(1)=2(1)4+9(1)3+11(1)2+4(1)−6

=2+9+11+4−6=20=0.

∴ 1 is not a zero of the polynomial f(x).

Again f(−1)=2(−1)4+9(−1)3+11(−1)2+4(−1)−6

=2−9+11−4−6=−6=00

∴ −1 is not a zero of the polynomial f(x).

Also f(−3)=2(−3)4+9(−3)3+11(−3)2+4(−3)−6

=162−243+99−12−6=00

∴ −3 is a zero of the polynomial f(x).

Thus 1 and −1 are not zeros of f(x), whereas −3 is zero of f(x).

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