Show that 1/√3 is irrational.
Answers
Answered by
3
hello proshan :))
well... hello dude you are going really great just refer to ncert very well i know you will do that.
-----------------------HERE'S YOUR SOLUTION------------------------------
let us rationalise this term.
then rationalization answer :-√3/3
now see here you know that '3' is rational for sure???
okk so let us now prove that the term root 3 is irrations.
let us assume that √3 is a rational number(contradiction).
now.
we can write it in the form p/q.
so some conditions:- here p and q are integers and q is not equal to 0 and also their hcf is 1.
now .
=> p/q=√3
(squarring)
=> p²/q²=3
=>p²=3q² ;;;;_ >>>> as here p is the factor and q is the multiple of p and respectively..
thus alltering...do the same by keeping a variable in place of q.
so.. now..
3 will be a factor of both p and q which contradicts are statement. that they bioth have a hcf of 1.
so we make a conclusion that although 2 is rational but √3 is irrational.
thanks :))
hope it helps you..
well... hello dude you are going really great just refer to ncert very well i know you will do that.
-----------------------HERE'S YOUR SOLUTION------------------------------
let us rationalise this term.
then rationalization answer :-√3/3
now see here you know that '3' is rational for sure???
okk so let us now prove that the term root 3 is irrations.
let us assume that √3 is a rational number(contradiction).
now.
we can write it in the form p/q.
so some conditions:- here p and q are integers and q is not equal to 0 and also their hcf is 1.
now .
=> p/q=√3
(squarring)
=> p²/q²=3
=>p²=3q² ;;;;_ >>>> as here p is the factor and q is the multiple of p and respectively..
thus alltering...do the same by keeping a variable in place of q.
so.. now..
3 will be a factor of both p and q which contradicts are statement. that they bioth have a hcf of 1.
so we make a conclusion that although 2 is rational but √3 is irrational.
thanks :))
hope it helps you..
Answered by
4
let us assume to the contrary that 1/√3 is rational number .
1/√3= P/Q { where p and Q are co-prime and Q not equal to 0}
√3 P =Q .1
√3 = Q/P
√3 = Irrational number
Q/P =Rational
Irrational not equal to rational.
This is a contradiction has arisen by the wrong assumption because of our incorrect assumption that 1/√3 is rational.
hence, 1/ √3 is irrational .{proved}
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