show that (-1+√3i)^3 is a real number
Answers
Answered by
1
Answer:
−1+
3
i)
3
⇒−1+3
3
i−3(−3)−3
3
i [∵(a−b)
3
=a
3
−b
3
−3ab(a−b)]
⇒−1+9=8
It is a real number.
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