Question

Show that 1/4-√15 - 1/√15-√14 + 1/√14-√13 - √13 =4

Answer 1

Answer:

42/63, 24/63, 14/63 [Arrange in descending order]. So, 2/3 ... (iv) à (c) Since3 * 1/4 = 1/4 + 1/4 + 1/4. Question 2: ... (vi) 5/2 * 6 (vii) 11 * 4/7 (viii) 20 * 4/5 (ix) 13* 1/3 ..

Answer 2

Answer:

Step-by-step explanation:

1/4-√15 - 1/√15-√14 + 1/√14-√13-√13 = 4

by rationalizing denominators we get

[(4+√15)/ 4²-√15²] - [(√15 + √14)/ √15² - √14²] + [(√14 + √13)/ √14²-√13²] - √13/1 =4

(4 + √15/ 16 - 15) - (√15 + √14/ 15 - 14) + (√14 + √13/ 14 - 13) - √13/1 =4

4 + √15 - √15 + √14 + √14 + √13 - √13/ 1 = 4 ( as the denominator is one)

    All the numbers gets cancel and left is 4

so,

4 =4

I hope I helped you to find your answer

and Maths is about practice the more you practice the more you become perfect.