Math, asked by sukhwinderkaurraheja, 10 months ago

Show that 1. (4/3m-3/4n)^2+2mn=16/9m^2+9/16n^2

Answers

Answered by weewee
5

To prove: (\frac{4}{3}m - \frac{3}{4}n)^{2} + 2mn = \frac{16}{9}m^{2} + \frac{9}{16} n^{2}

Proof:

LHS = (\frac{4}{3}m - \frac{3}{4}n)^{2} + 2mn

       = (\frac{4}{3}m)^{2} + (\frac{3}{4}n)^{2} - 2mn + 2mn

       =\frac{16}{9}m^{2} + \frac{9}{16}n^{2}

       =RHS

Hence Proved

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