Show that 1. (4/3m-3/4n)^2+2mn=16/9m^2+9/16n^2
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Answer:
Use of algebraic identities:
(i) (a - b)² = a² - 2ab + b²
L.H.S. = (4/3 m - 3/4 n)² + 2mn
= (4/3 m)² - 2 * 4/3 m * 3/4 n + (3/4 n)² + 2mn
= 16/9 m² - 2mn + 9/16 n² + 2mn
= 16/9 m² + 9/16 n² = R.H.S.
Hence, proved.
(ii) a² - b² = (a + b) (a - b)
L.H.S. = (4pq + 3q)² - (4pq - 3q)²
= (4pq + 3q + 4pq - 3q) (4pq + 3q - 4pq + 3q)
= 8pq * 6q
= 48pq² = R.H.S.
Hence, proved.
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