Show that (1, 5) as well as (-2, −1) are the solutions of the equation 2x − y + 3= 0. Find two more solutions. How many solutions can we find?
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2x−3y+17=0⇒2x=3y−7⇒x=
2
3y−7
at y = 1 x = -2
at y = -1 x = -5
so (-2, 1) (-5, -1)are the 2 solution
I hope it's help you
and please give me one thanks
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