Question

Show that 1^99+ 2^99 + 3^99 + 5^99 is divisible by 5

Answer 1

since they're all to the 99th power, you can say that they equal.

(1 + 2 + 3 + 4 + 5)^99 or

(15)^99.

Since 15 ends in a 5, you know that it will always be divisible by 5.

Answer 2

Answer:

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