Question

show that (1-alpha)(1- beta) (1-alpha²)(1-beta²)​

Answer 1

Answer:

α,β are the roots of x

2

−2x+4=0

⇒α+β=2,αβ=4

α

2

+β

2

=(α+β)

2

−2αβ

=2

2

−2(4)

=4−8=−4

α

3

+β

3

=(α+β)

3

−3αβ(α+β)

=2

3

−3(4)(2)

=8−24=−16

Now, α

5

+β

5

=(α

3

+β

3

)(α

2

+β

2

)−α

3

β

2

−α

2

β

3

=(α

3

+β

3

)(α

2

+β

2

)−(αβ)

2

(α+β)

=(−16)(−4)−(4)

2

(2)

=64−32=32

Answer 2

Answer:

Q.1. Find the Load Line and Q-point for the Bi-Polar Junction Transistor.

VBB= 20 V

RB= (Roll. No. of Student) KΩ

Rc = 5 KΩ

Vcc= 20 V

βdc = 100

Note: Use the solved example in BJTs as a reference.