Question

show that -1 and -3/2 are zeroes of the polynomial 6x^3+11x^2-x-6​

Answer 1

Answer:

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Step-by-step explanation:

x=-1, x=-3/2

=(x+1) (2x+3)

=2x^2+3x+2x+3

=2x^2+5x+3 ......(i)

divide (i) with polynomial given in question then we will get the perfect remainder if they are its zeroes

(6x^3+11x^2-x-6)/(2x^2+5x+3)