Question

show that 1 by 2 and minus 3 by 2 are the zeroes of the polynomial 4X2 plus 4X minus 3 verify relationship between zeroes and the coefficient​

Answer 1

Step-by-step explanation:

the answer is in the picture

Answer 2

Answer:

$4 {x}^{2} + 4x - 3 = 0 \\ 4 {x}^{2} + 6x - 2x - 3 = 0 \\ 2x(2x + 3x) - 1(2x + 3) = 0\\ (2x - 1)(2x + 3) = 0 \\ \\ \\ 2x = 1 \\ x = \frac{1}{2} - - - - - \alpha \\ \\ \\ 2x = - 3 \\ x = \frac{ - 3}{2} - - - - \beta$

Step-by-step explanation:

$\alpha + \beta = \frac{ - b}{a} \\ \frac{1}{2} + \frac{ - 3}{2} = \frac{ - (4)}{4} \\ \frac{ - 2}{2} = - 1 \\ - 1 = - 1$

$\alpha \beta = \frac{c}{a} \\ \frac{1}{2} \times \frac{ - 3}{2} = \frac{ - 3}{4} \\ \ \frac{ - 3}{4} = \frac{ - 3}{4}$

HENCE PROVED❕❕❕