Show that (1/cos ∅) - cos ∅ = tan ∅ .sin ∅
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20
LHS = (1/cos ∅) - cos ∅
= (1 - cos²∅)/cos ∅
= sin² ∅/cos∅
= (sin∅/cos∅) × sin∅
= tan ∅ .sin ∅
= RHS
hence proved!
here, (1-cos²A) = sin²A
sinA/cosA = tan A
= (1 - cos²∅)/cos ∅
= sin² ∅/cos∅
= (sin∅/cos∅) × sin∅
= tan ∅ .sin ∅
= RHS
hence proved!
here, (1-cos²A) = sin²A
sinA/cosA = tan A
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7
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