Question

show that 1/cos tita-cos tita=tan tita*sin tita​

Answer 1

Answer:

$\frac{1}{ \cos( \alpha ) } - \cos( \alpha ) = \tan( \alpha ) \sin( \alpha ) \\ lhs = \frac{1}{ \cos( \alpha ) } - \cos( \alpha ) \\ = \frac{1 - { \cos( \alpha ) }^{2} }{ \cos( \alpha ) } \\ = \frac{ { \sin( \alpha ) }^{2} }{ \cos( \alpha ) } \\ = \tan( \alpha ) \sin( \alpha )$

Answer 2

Step-by-step explanation:

1/cosA-cosA=1-cis^2A/cosA

=sin^2A/cosA

=sinA*TanA

hence proved.