Question

Show that
(1+cosA)/(1-cosA) = (tan^2 A)/(secA-1)^2


Use only first three trigonometric identities please

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Let us take

RHS=

$\frac{ {tan(a)}^{2} }{ ({sec(a) - 1})^{2} }$

tan(a)^2 can be written as sec(a)^2-1

$\frac{ { \sec(a) }^{2} - 1 }{ ({sec(a) - 1})^{2} } = \frac{(sec(a) + 1)( \sec(a) - 1) }{(sec(a) - 1)(sec(a) - 1)}$

$\frac{ \sec(a) + 1 }{ \sec(a) - 1 } = \frac{ \frac{1}{ \cos(a) } + 1 }{ \frac{1}{ \cos(a) } - 1}$

$\frac{1 + \cos(a) }{1 - \cos(a) }$

Hence showed

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