Question

show that
(1 + cot∅ - cosec ∅)(1+tan∅+sec∅)=2

Answer 1

Answer:

hope this answer helped you

Step-by-step explanation:

(sin+cos)²=sin²+cos²+2sincos=1+2sincos

Answer 2

Answer:

so LHS=RHS=2

Step-by-step explanation:

(1+cotØ-cosecØ) (1+tanØ+secØ)

= 1+tanØ+secØ+cotØ+cotØtanØ+cotØsecØ-cosecØ-cosec∅tanØ-cosecØsecØ

= 1+tanØ+secØ+cotØ+1+cosecØ-cosecØ-secØ-cosecØsecØ

= 1+1+tanØ+cotØ-cosecØsecØ

= 2+(sinØ/cosØ)+(cosØ/sinØ)-[1/(sinØcosØ)]

= 2+[(sin²Ø+cos²Ø)/(sinØcosØ)]-[1/(sinØcosØ)]

= 2+[1/(sinØcosØ)]-[1/(sinØcosØ)]

= 2+[(1-1)/(sinØcosØ)]

= 2+[0/(sinØcosØ)]

= 2+0

= 2

Hence Proved

Hope it helps, mark it as the brainliest answer