Math, asked by konain97, 11 months ago

show that 1 + cotA -cosA÷cotA + cosA=cosecA-1÷cosecA+1​

Answers

Answered by abhaypatel85
3

Lhs = (cotA - cosA)/(cotA+cosA)=(cosA/sinA - cosA)/(cosA/sinA+ cosA)=cosA(1/sinA - 1)/cosA(1/sinA+ 1)= (1/sinA -1)/(1/sinA+1)=(cosecA-1)/(cosecA+1) since 1/sinA= cosecA=rhs

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