Question

show that (1+i to the power 14 + i to the power of 18+ i to the power of 22) is a real number​

Answer 1

Step-by-step explanation:

Soln,

[ {(1 + i) ^ 14 + i}^18 + i ]22

= (1 + i)^(14 + i)(18 + i)22

= (1 + i)^(256+32i+i^2) 22

= (1 + i)^ ( i + 16)^ 22

= (1 + i)^ (22i + 352) ^2

which is a real number