Show that 1 is a zero of the polynomial p(x) = x³
− 6x² +11x −6
Answers
Answered by
1
Answer:
This is your answer
Step-by-step explanation:
p(1) = 1^3-6(1)^2+11-6
=1-6+11-6
=1-6+5
=1-1
=0
Hence proved
Answered by
1
Answer:
for 1 to be a zero,when substituting by x, we get the result as 0.if not it is not a root.
when substituting this equation by 1,
(1)cube-6(1 square)+11(1)-6
1-6+11-6
i.e,-5+5=0
as the polynomial becomes zero when substituting by 1 we get 0
hence it is a root
Answered by
0
Answer:
for 1 to be a zero,when substituting by x, we get the result as 0.if not it is not a root.
when substituting this equation by 1,
(1)cube-6(1 square)+11(1)-6
1-6+11-6
i.e,-5+5=0
as the polynomial becomes zero when substituting by 1 we get 0
hence it is a root
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