Question

show that 1+sin theta/cos theta =1/sec theta-tan theta​

Answer 1

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Step-by-step explanation:

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Answer 2

$\frac{1 + sin \theta}{cos \theta} \\ \\ = \frac{1}{cos \theta} + \frac{sin \theta}{cos \theta} \\ \\ = sec \theta + tan \theta \\ \\ = \frac{sec \theta + tan \theta}{ {sec}^{2} \theta - {tan}^{2} \theta } \\ \\ = \frac{1}{sec \theta - tan \theta}$