Question

show that :-
(1-sin2 theta) (sec2 theta) = 1​

Answer 1

Answer:

(1-0)(1)=1

0×1=1

0

Step-by-step explanation:

Not 1 answer is 0

Answer 2

We have,

LHS = (1−sin² θ) sec² θ

⇒LHS = cos² θ sec² θ [ ∵1 - sin² = cos² θ ]

$⇒LHS = {cos}^{2} \: θ \: ( \frac{1}{cos {}^{2} \: θ })$

$[∵ \: sec \: θ = (\frac{1}{cos \: θ} ) \: ]$

⇒ LHS = 1 = RHS