Show that (1-sina+cosa)^2 =2(1+cosa)(1-sina)
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Answer:
((1-sina)+cosa)^2
(1-sina)^2+cosa^2+2(1-sina)cosa
1+sin^2a-2sina+cosa^2+2(1-sina)cosa
2-2sina+2(1-sina)cosa
2(1-sina)+2(1-sina)cosa
2(1-sina)(1+cosa)
Explanation:
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