Show that 1≤ sintheta + theta ≤ √2
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Answer:
√2>=sin theta+coa theta>=1
Step-by-step explanation:
sin theta lies in (-1,1)
cos theta lies in (-1,1)
now assuming u add the both...
say sin0+cos0 you'll have 0+1=1
or. sin30+cos30 you'll have 1/2+√3/2
sin45+cos45=1/√2+1/√2=2/√2=√2
sin60+cos60=1/2+√3/2=1+√3/2
sin90+cos90=1+0=1
so we can say that all the values of sin and cos additons
√2>=cos theta+sin theta>=1 Ans
Hope that was helpful friend
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