Question

show that [1+tan^2 a/1+cot^2 a]=[1+tan a/1- cot a]^2=tan^2 a

Answer 1

Here is your que's answer dear.

Answer 2

Answer:

I will tell answer for your question.

Step-by-step explanation:

LHS

1+tan^2 A/1+cot^2 A=sec^2 A/cosec^2 A=tan^2 A

(1-tan A)^2/(1-cot A)^2=1+tan^2 A-2 tan A/1+cot^2 A-2 cot A

=sec^2 A-2 tan A/cosec^2 A-2 cot A=[(1/cos^2 A)-(2 sin A/cos A)]/[(1/sin^2 A)-(2 sin A/cos A)]=[(1-2 sin A*cos A)/(cos^2 A)]/[(1-2 sin A*cos A)/(sin^2 A)]=tan^2 A