Math, asked by jagadeeshirrinki963, 5 months ago

show that 1-tan²A/cot²A-1=tan²A​

Answers

Answered by ishwardeswal096
1

Step-by-step explanation:

LHS:

=(1-tan-A) / (cot?A-1)

=[1-(sinA/cos?A)] / [(cos?A/sin?A)-1]

=[(cos?A-sin2A)/cos?A]=[(cos?A-sin?A)/ sin A1 [CANCELLING cos?A-sin?A from both the

numerator and denominator ]

=(1/cos-A)-(1/sin-A)

=sin?A/cos?A

=tan?A

=RHS

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