show that 1-tan²A/cot²A-1=tan²A
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Step-by-step explanation:
LHS:
=(1-tan-A) / (cot?A-1)
=[1-(sinA/cos?A)] / [(cos?A/sin?A)-1]
=[(cos?A-sin2A)/cos?A]=[(cos?A-sin?A)/ sin A1 [CANCELLING cos?A-sin?A from both the
numerator and denominator ]
=(1/cos-A)-(1/sin-A)
=sin?A/cos?A
=tan?A
=RHS
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