Math, asked by MohamedDanish4311, 18 days ago

Show that 1+tan²A/secA=(1+tanA/1-cotA)²=tan²A

Answers

Answered by Diliptalapda

0

Answer:

$\frac{1 + {tan}^{2}a }{sec \: a} = ( \frac{1 + tan \: a}{1 + cot \: a} ) ^{2} = {tan}^{2} a$

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