show that 10,11,12 cannot be term of a g .p.
Answers
Answered by
1
hello Frnd
A sequence is GP when it's there is a common ration between them.
GP stands for Geometric progression.
To show 10,11,12 cannot be in GP, we have to assume it is a GP
And if it's a GP, there must be common ratio
a2/ a1 = a3/a2
11 / 10 = 12 /11
Since a2 /a1 is not equal to a3/ a2
There fore it is not a GP , hence proved
hope it helps
#jerri
A sequence is GP when it's there is a common ration between them.
GP stands for Geometric progression.
To show 10,11,12 cannot be in GP, we have to assume it is a GP
And if it's a GP, there must be common ratio
a2/ a1 = a3/a2
11 / 10 = 12 /11
Since a2 /a1 is not equal to a3/ a2
There fore it is not a GP , hence proved
hope it helps
#jerri
muskan164:
nyc bahut fast answer mila
Similar questions