show that (11, 2) is the centre of the coicle
passing through the points (1, 2), (3,-4) and (5, 6)
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Circle passing through three points (1,2) , (3,-4) and (5,-6) . Put (1,2) in equation of circle. 1² + 2² + 2g(1) + 2f(2) + c = 0
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