Show that√11 is an irrational number.
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Answered by
5
hey mate here is your answer..
A rational number can be written in the form of p/q where q ≠ 0 and p , q are non negative number.
√11 = p/q ....( Where p and q are co prime number )
Squaring both side !
11 = p²/q²
11 q² = p² ......( i )
p² is divisible by 11
p will also divisible by 11
Let p = 11 m ( Where m is any positive integer )
Squaring both side
p² = 121m²
Putting in ( i )
11 q² = 121m²
q² = 11 m²
q² is divisible by 11
q will also divisible by 11
Since p and q both are divisible by same number 11
So, they are not co - prime .
Hence Our assumption is Wrong √11 is an irrational number.
hope it helps you..
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Answered by
2
assume √11 is rational
√11= a/b( where a and b are number not co prime)
canceling common factord
√11=p/q(where p and q are co prime)
squaring both sides
(√11)²=(p/q)²
11=p²/q²
11q²=p²
therefore √11 divides p² as well as p
p=11×C
substituting p in 11q²=p²
11q²=(11c)²
11q²=121c²
q²=121c²/11
q²=11c²
therefore √11 divides q² as well as q
this is not possible as q and p are co prime
therefore √11 is an irrational number
pls do mark as brainliest. all the best for exams and feel free to ask doubts
√11= a/b( where a and b are number not co prime)
canceling common factord
√11=p/q(where p and q are co prime)
squaring both sides
(√11)²=(p/q)²
11=p²/q²
11q²=p²
therefore √11 divides p² as well as p
p=11×C
substituting p in 11q²=p²
11q²=(11c)²
11q²=121c²
q²=121c²/11
q²=11c²
therefore √11 divides q² as well as q
this is not possible as q and p are co prime
therefore √11 is an irrational number
pls do mark as brainliest. all the best for exams and feel free to ask doubts
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