show that 11x power 2 - 19 y power 2
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Since x3+6∗x2>=0x3+6∗x2>=0
Then, x2(x+6)>=0x2(x+6)>=0
i.e (x−0)2(x−(−6))>=0(x−0)2(x−(−6))>=0
This implies that\(x>=-6\)
Hence, x=-2 is a valid root, and sum of all roots should bex=3+(−2)=1x=3+(−2)=1
Please let me know where I am going wrong.
Then, x2(x+6)>=0x2(x+6)>=0
i.e (x−0)2(x−(−6))>=0(x−0)2(x−(−6))>=0
This implies that\(x>=-6\)
Hence, x=-2 is a valid root, and sum of all roots should bex=3+(−2)=1x=3+(−2)=1
Please let me know where I am going wrong.
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