show that 12^n cannot end with digit 0 or 5 hr any natural number n
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Here, Number=12n where n stand for any natural number . Now , For 12n to end with 0, it should have 2 as well as 5 in its Prime factors to end with 0, Also to end with 5 , it requires at least a single multiple of 5 in its Prime Factors, So 12n cannot end with the digit 0 or 5
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